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您好,社区,有人知道如何将多个参数传递给odata吗? 看起来我是这样做的:
nextActivities:function(){ var oTableClear = this.getView()。byId(" tabla"); oTableClear.destroyItems(); //Obtenemos la fecha y Asesor var fecha = this.byId(" lFecha")。getText(); var asesor = this.byId(" usuario")。getValue(); var oTable = this.getView()。byId(" tabla"); var sURI ="/img/sap/opu/odata/SAP/ZERP_ACTIVIDADES_SRV"; var oDataModel = new ODataModel(sURI,true); var oModel = new sap.ui.model.json.JSONModel(); var oFilter = new Filter(" Asesor"," EQ",asesor); oDataModel.read("/img/ReservaNextSet",{ 过滤器:[oFilter], 成功:函数(oData,响应){ var oResults = oData.results; oModel.setData(oData.results); oTable.setModel(oModel); } }); },
我尝试了此操作,但出现错误:
[new Filter(" Asesor"," EQ",asesor), new Filter(" timestamp"," EQ",fecha)]; 或这样的错误: var oFilter,aFilter; oFilter = []; oFilter.push(new Filter(" Asesor"," EQ",asesor)); oFilter.push(new Filter(" timestamp"," EQ",fecha)); oDataModel.read("/img/ReservaNextSet",{ 过滤器:[oFilter], 和这个:(没有错误,但是在表中it_filter_select_options没有捕获到任何东西) var oFilter0 = new Filter(" Asesor"," EQ",asesor); var oFilter1 = new Filter(" timestamp"," EQ",fecha); var oFilter = new Filter([oFilter0,oFilter1],false); oDataModel.read("/img/ReservaNextSet",{ 过滤器:[oFilter], 像这样: var oFilter,aFilter; oFilter = []; oFilter.push(new Filter(" Asesor"," EQ",asesor)); oFilter.push(new Filter(" timestamp"," EQ",fecha)); aFilter = new Filter({filters:oFilter,and:false}); oDataModel.read("/img/ReservaNextSet",{ 过滤器:[aFilter], 成功:函数(oData,响应){ var oResults = oData.results; oModel.setData(oData.results); oTable.setModel(oModel); }
(11.6 kB)
这是解决方案:注意过滤器:oFilter不是[oFilters],因为它已经是一个数组////数据处理复杂性nextActivities:function(){var oTableClear = this.getView()。byId (" tabla"); oTableClear.destroyItems();
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