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专家们,
执行下面的查询后,我从" catalogA"和" catalogB"两个目录中获得所有产品的UNION
SELECT uniontable.PK,uniontable.creationtime按时间从
(
{{
选择{p:mode},{p:brandno},{creationtime} AS创建时间,来自{Product AS p JOIN catalogversion AS AS cv ON
{p:catalogversion} = {cv:pk}加入目录as cat on {p:catalog} = {cat:pk}}
{p.code} ='145'并且{cv:version} ='Staging'和{cat:id} ='catalogA'
}}
全联盟
{{
选择{p:mode},{p:brandno},{creationtime} AS创建时间,来自{Product AS p JOIN catalogversion AS AS cv ON
{p:catalogversion} = {cv:pk}加入目录as cat on {p:catalog} = {cat:pk}}
{p.code} ='123'并且{cv:version} ='Staged'并且{cat:id} ='catalogB'
}}
)uniontable ORDERR BY TIMECREATED
我只需要UNION查询的CatalogA中的产品,所以我做了如下的子查询,但是它抛出错误。 任何帮助将不胜感激?
SELECT uniontable.PK,uniontable.creationtime按{产品AS p JOIN catalogversion AS cv ON的时间递增
{p:catalogversion} = {cv:pk}加入目录as cat on {p:catalog} = {cat:pk}}
{cv:version} ='Staging'和{cat:id} ='catalogA'IN
(
{{
选择{p:mode},{p:brandno},{creationtime} AS创建时间,来自{Product AS p JOIN catalogversion AS AS cv ON
{p:catalogversion} = {cv:pk}加入目录as cat on {p:catalog} = {cat:pk}}
{p.code} ='145'并且{cv:version} ='Staging'和{cat:id} ='catalogA'
}}
全联盟
{{
选择{p:mode},{p:brandno},{creationtime} AS创建时间,来自{Product AS p JOIN catalogversion AS AS cv ON
{p:catalogversion} = {cv:pk}加入目录as cat on {p:catalog} = {cat:pk}}
{p.code} ='123'并且{cv:version} ='Staged'并且{cat:id} ='catalogB'
}}
)uniontable ORDERR BY TIMECREATED
您可以这样做:
如果要使用
JOIN
,则可以使用以下查询,与上面给出的查询等效:一周热门 更多>