想要在SAP UI5中将标题值显示为行,将行值显示为列

2020-09-14 13:20发布

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我的问题是关于:我正在做动态表并获取结果,但我想以不同的方式显示,例如转置。 因为我有N个列值和5个行值。 所以我想以垂直方式显示表格,例如转置(列值应显示为行,行值应显示为列)

var columnData = [{columnName:" Attr1"},{columnName:" Attr2"},{columnName:" Attr3"},{columnName:" Attr4"},{columnName:" Attr5"},{columnName: " Attr6"},{columnName:" Attr7"},{columnName:" Attr8"},{columnName:" Attr9"},{columnName:" Attr10"},{columnName:" Attr11"}]];

var rowData = [{Attr1:" Mat1",Attr2:" Product1",Attr3:" Reason1",Attr4:" Global1",Attr5:"印度",Attr6:"品牌1",Attr7:" Size-L ",Attr8:" Falv1",Attr9:" Mat1",Attr10:" Cat1",Attr11:" UOM1"},{Attr1:" Mat2",Attr2:" Product2",Attr3:" Reason2",Attr4:" Global2 ",Attr5:"英国",Attr6:"品牌2",Attr7:" Size-M",Attr8:" Falv2",Attr9:" Mat2",Attr10:" Cat2",Attr11:" UOM2"},{Attr1: " Mat3",Attr2:" Product3",Attr3:" Reason3",Attr4:" Global3",Attr5:" US",Attr6:" Brand3",Attr7:" Size-XL",Attr8:" Falv3",Attr9: " Mat3",Attr10:" Cat3",Attr11:" UOM3"}];

这是我得到的实际结果:

我想要的预期结果:

感谢与问候

Preeti

(18.9 kB)
1条回答
Cikesha
2020-09-14 13:50 .采纳回答

大家好,

我得到了转置表解决方案。 这是代码:

//*********查看代码*************//

<表项目=" {路径:'DT>/rowData2',工厂:'.productListFactory'}" column =" {DT>/colData2}" mode =" SingleSelectMaster" select =" handleGLItemPress">

<列>

//***************控制器代码*****************//

onInit:function(){

var data = {};

var colData = [

{colName:" Attr1"},

{colName:" Attr2"},

{colName:" Attr3"}]

var rowData = [

{Attr1:" Mat1",Attr2:" Mat2",Attr3:" MAt3"},

{Attr1:" Mat11",Attr2:" Mat22",Attr3:" MAt33"}]

data.colData2 = [];

data.colData2.push({colName:""})

data.rowData2 = [];

对于(var i = 0; i

{

data.colData2.push({colName:""})

}

for(colData中的var i){

var cName,obj = {};

for(var j = 0; j

{

cName = colData [i] [" colName"];

obj [cName + j] = rowData [j] [cName];

}

obj [" colName"] = cName;

data.rowData2.push(obj);

}

var oModel = new sap.ui.model.json.JSONModel(data);

this.getView()。setModel(oModel," DT");

},

productListFactory:function(sId,oContext){

var oUIControl = [];

var sObj = oContext.getObject();

oUIControl.push(new sap.m.Label({text:sObj.colName}));

for(sObj中的var i){

if(i ==" colName")

{

继续;

}

oUIControl.push(new sap.m.Label({text:sObj [i]})));

}

返回新的sap.m.ColumnListItem({cells:oUIControl});

},

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