DECLARE @从DATE，@到DATE
SET @From =''
SET @To =''
选择
A.DocNum AS [发票编号]，A.CardName AS [客户名称]，
当A.DocType ='S'然后B.LineTotal ELSE 0 END AS [服务总计]时，
当A.DocType ='I'时的情况B.LineTotal ELSE 0 END AS [项目总计]
从OINV A
A.DocEntry上的INNER1 INV1 B = B.DocEntry
@From和@To之间的A.DocDate
全联盟
-取消项目
选择
A.DocNum AS [发票编号]，A.CardName AS [客户名称]，
当A.DocType ='S'然后-B.LineTotal ELSE 0 END AS [服务总计]时的情况，
当A.DocType ='I'时的情况-B.LineTotal其他0结束为[项目总计]
从ORIN A
内连接RIN1 B在A.DocEntry = B.DocEntry
@From和@To之间的A.DocDate
{var%20f='http://v.t.sina.com.cn/share/share.php?appkey=1515056452',u=z||d.location,p=['&url=',e(u),'&title=',e(t||d.title),'&source=',e(r),'&sourceUrl=',e(l),'&content=',c||'gb2312','&pic=',e(p||'')].join('');function%20a(){if(!window.open([f,p].join(''),'mb',['toolbar=0,status=0,resizable=1,width=440,height=430,left=',(s.width-440)/2,',top=',(s.height-430)/2].join('')))u.href=[f,p].join('');};if(/Firefox/.test(navigator.userAgent))setTimeout(a,0);else%20a();})(screen,document,encodeURIComponent,'','','http://www.easysap.com/data/attach/logo/logo.png', '推荐 沉淀 的问题《具有项目和服务拆分的AR发票查询》','https://www.easysap.com/answer/61365/171828.html','页面编码gb2312|utf-8默认gb2312'));){kind=link}
嗨，
尝试一下
DECLARE @从DATE，@到DATE SET @From ='' SET @To ='' 选择 A.DocNum AS [发票编号]，A.CardName AS [客户名称]， 当A.DocType ='S'然后B.LineTotal ELSE 0 END AS [服务总计]时， 当A.DocType ='I'时的情况B.LineTotal ELSE 0 END AS [项目总计] 从OINV A A.DocEntry上的INNER1 INV1 B = B.DocEntry @From和@To之间的A.DocDate 全联盟 -取消项目 选择 A.DocNum AS [发票编号]，A.CardName AS [客户名称]， 当A.DocType ='S'然后-B.LineTotal ELSE 0 END AS [服务总计]时的情况， 当A.DocType ='I'时的情况-B.LineTotal其他0结束为[项目总计] 从ORIN A 内连接RIN1 B在A.DocEntry = B.DocEntry @From和@To之间的A.DocDate一周热门 更多>